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CBSE 10 - Statistics

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if the mean of a data is 27 and its median is 33 then the mode is

2 / 25

Which one of the following measures is determined only after the construction of cumulative frequency distribution?

 

3 / 25

The mean of 2,7,6 and \(x\) is 15 and the mean of \(18,16, x and y\)  is 10. What is the value of \(y\)?

4 / 25

If the median of the data \(4,7,x-1,x-3,16,25\) , written in ascending order, is 13 then \(x\) is equal to

5 / 25

The mean of 20 numbers is zero. Of them, at the most, how many may be greater than zero?

6 / 25

The median of first 8 prime numbers is

7 / 25

For a symmetrical frequency distribution, we have

    1. Mean<mode<median
    2. Mean>mode>median
    3. Mean=mode=median
    4. mode=\(\frac{1}{2}\)(mean+median)

8 / 25

The median and mode of a frequency distribution are 26 and 29 respectively. Then, the mean is

9 / 25

The mean and mode of a frequency distribution are 28 and 16 respectively. The median is

10 / 25

If the mean and median of a set of numbers are 8.9 and 9 respectively then the mode will be

11 / 25

Median=?

    1. \(l+{h\times \frac{(\frac{N}{2}-cf)}{f} }\)
    2. \(l+{h \times \frac{(cf-\frac{N}{2})}{f}}\)
    3. \(l-{h\times \frac{(\frac{N}{2}-cf)}{f} }\)
    4. None of these

12 / 25

Mode=?

    1. \(x_k +h.{\frac{(f_(k-1)-f_k)}{(2f_k -f_k-1 -f_k+1)}}\)
    2. \(x_k +h.{\frac{(f_k-f_k-1)}{2f_k -f_k-1 -f_k+1}}\)
    3. \(x_k +h.{\frac{(f_k - f_k-1)}{(f_k -2f_k-1 -f_k+1)}}\)
    4. \(x_k +h.{\frac{(f_k - f_k-1)}{(f_k -f_k-1 -2f_k+1)}}\)

13 / 25

If the ‘less than type’ ogive and ‘more than type’ ogive intersect each other at (20.5,15.5) then the median of the given data is

14 / 25

the relation between mean, mode and median is

    1. \(mode=(3\times mean)-(2\times median)\)
    2. \(mode=(3\times median)-(2\times mean)\)
    3. \(median=(3\times mean)-(2\times mode)\)
    4. \(mean=(3\times median)-(2\times mode)\)

15 / 25

while computing the mean of the grouped data, we assume that the frequencies are

 

 

16 / 25

In the formula, \(\overline {x}={A+\frac{\sum f_i d_i}{\sum f_i}}\) for finding the mean of the grouped data, the\(d_I\)  ’s are the deviations from \(A\)  of

 

17 / 25

For finding the mean by using the formula, \(\ovrerline{x}=A+h(\frac{\sum f_i u_i}{\sum f_i})\), we have \(u_i\)=?

    1. \(\frac{(A-x_i)}{h}\)
    2. \(\frac{(x_i -A)}{h}\)
    3. \(\frac{(A+x_i)}{h}\)
    4. \(h(x_i-A)\)

18 / 25

If \(x_i\)’s are the midpoints of the class intervals of a grouped data, \(f_I\)'s are the corresponding frequencies and \(\overline {x}\) is the mean then \(\sum f_i (x_i-\overline{x})=\)?

19 / 25

The abscissa of the point of intersection of the less than type and of the more than type cumulative frequency curves of a grouped data gives its

 

20 / 25

The cumulative frequency table is useful determining the

 

21 / 25

The median of a frequency distribution is found graphically with help of

 

22 / 25

The mode of a frequency distribution is obtained graphically from

 

23 / 25

Which of the following measures of central tendency is influenced by extreme values?

24 / 25

Which of the following cannot be determined graphically?

 

25 / 25

which of the following is not a measure of central tendency?

 

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